分解因式!
b/a - 2 + a/b
thx!
F.2 MATHS!
2006-11-16 8:11 am
回答 (4)
2006-11-16 8:17 am
✔ 最佳答案
b/a - 2 + a/b= b^2 / (ab) - (2ab)/ (ab) + a^2 / (ab)
= (b^2 - 2ab + a^2) / (ab)
= (a + b)^2/ (ab)
參考: me
2006-11-17 12:36 am
b/a-2+a/b
=b/a-2-b/a
=(b/a)(-2)
2006-11-16 16:38:37 補充：
上那一些全是錯!!!!!!!!!!我今天剛學完一定win
=b/a-2-b/a
=(b/a)(-2)
2006-11-16 16:38:37 補充：
上那一些全是錯!!!!!!!!!!我今天剛學完一定win
參考: 自己於中二學的因子分解
2006-11-16 8:18 am
b/a - 2 + a/b
= b^2/ab - 2ab/ab + a^2/ab
= (b^2 + 2ab + a^2)/ab
= (a+b)^2/ab
= b^2/ab - 2ab/ab + a^2/ab
= (b^2 + 2ab + a^2)/ab
= (a+b)^2/ab
2006-11-16 8:18 am
u mean factorize?
b/a-2+1/b
= (bxb - 2ab + axa) / (ab)
= (b - a) (b - a)/ (ab)
b/a-2+1/b
= (bxb - 2ab + axa) / (ab)
= (b - a) (b - a)/ (ab)
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