指數方程 f1架

2006-11-16 2:34 am
(-4)^3-(-6)^2+(-5)^3

=-225

(-8h 2次方k 9次方)(6h 4次方k 3次方)/(-12h 5次方)
=4hk 12次方
why?
要詳細過程+解釋

回答 (2)

2006-11-16 2:50 am
(-4)³-(-6)²+(-5)³
= - 64 - 36 - 125
= -100 - 125
= -255
so (-4)³-(-6)²+(-5)³ = -255
(-8h² k^9)(6h^4 k³) / (-12h ^5)
= -48h^(2 + 4) k^(9 + 3) / (-12h^5)
= -48h^6 k^12 / -12h^5
= 4h^(6 - 5)k^12
= 4hk^12
參考: me
2006-11-16 2:47 am
首先你要明白.. 以下
(2^3)(2^5) = 2^8
即係.. (A^n)(A^m) = A^(n+m) [A = 任何數]
(2^5)/(2^3) = 2^2
即係.. (A^n)/(A^m) = A^(n-m)

之後要你條數...
(-8h^2)(k^9)(6h^4)(k^3)/(-12h^5)
= -48(h^6)(k^12) / -12(h^5)
= 4h^(6-5)k^12
= 4hk^12


收錄日期: 2021-04-13 16:52:12
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