方程式問題~~~~~~~~急

1-2[3-(x/2-1)]=x/4+1
1-2[3-x/2+1]=x/4+1
1-6+x-2=x/4+1
-7+x=x/4+1
-28+4x=x+4
4x-x=4+28
3x=32
x=10and2over3

1-6-(-2分之-2x+2)=4分之x+1

-5-(2分之2x+2)=4分之x+1

-5=(4分之x+1)+(2分之2x+2)

-5=(4分之x+1)+(4分之4x+4)

-5=4分之5x+5

5x+5=-20

x=-5

錯左唔好話我.....

1-2(3-(x-1)/2) = (x+1)/4 (如果2分之x-1的意思是(x-1)/2)
1-6+(x-1) = (x+1)/4
1-6+x-1 = (x+1)/4
-6+x = (x+1)/4
-24+4x = x+1
3x = 25
x = 25/3

1-2(3-((x/2)-1)) = (x/4)+1 (如果2分之x-1的意思是(x/2)-1)
1-6+2((x/2)-1) = (x/4)+1
1-6+x-2 = (x/4)+1
x-(x/4) = 8
3x/4 = 8
x = 32/3

1.1-2[3-(2分之x-1)=4分之x+1

1.1-2[3-(2分之x)=4分之x+1 +1