數學問題...

a^-4a+3

(a-3)(a-1)
= a*a - a*1 - 3*a + (-3)*(-1)
= a的二次方 -4a +3

(a-3)(a-1)
=a^2-a-3a+3
=a^2-4a+3

(a-3)(a-1)
=a^ -1a-3a+1

(a-3)(a-1) = a^2 - 3a - a + 3 = a^2 - 4a +3

* a ^ 2 = a 的二次方.

Tis method is called expansion.It means we need to make the factor (the 括號) to be the simpliest answer.

In order to do that, you should know the format:
( A + B) ( C + D) = AC + BC + AD + BD

Then , use the method to think about your question.

Remember that whenever there're same monomial (同項) , simplify them!!!!!!!

(a-3)(a-1)

= a2– a – 3a + 3

= a2 –4a+3


* that a2 = a xa , i don't know how to type two square

(a-3)(a-1)
=a^2-4a+3

因為(x-y)(z-a)
=xz-ax-yz+ay
所以(a-3)(a-1)
=a^2-a-3a+3
=a^2-4a+3

（a-3)(a-1)
=a２次－３a-a+3
=a２次-4a+3

(a-3)(a-1)
=a2(2次方)-a-3a+3
=a2-4a+3

a=什麼？

(a-3)(a-1)
a-3=0 or a-1=0
a=3 or a=1

(a-3)(a-1)
=a(a-1)-3(a-1)
=a^2-a-3a+3
=a^2-4a+3

^ stand for "to the power "..