急急急!!!10分!!!!數學~~

2006-11-13 1:07 am
1. 2xy+3=2x-y  [x]

  3x+1 
2.y=____    [x]
  1-3x

  2x+3
3.y=____    [x]
  x-1

ans:
  y+3
1.x=_____
  2(1-y)

  y-1
2.x=_____
  3(y+1)

  y+3
3.x=___
  y-2
              ***要steps***

回答 (3)

2006-11-13 1:22 am
✔ 最佳答案
1. 2xy+3=2x-y  [x]
y+3 = 2x - 2xy
y+3 = x(2 - 2y)
y+3 / 2 - 2y = x
y+3 / 2(1-y) = x
x = y+3 / 2(1-y)
ans:
  y+3
x=_____
  2(1-y)

  3x+1 
2.y=____    [x]
  1-3x

y(1 - 3x) = 3x+1
y - 3xy = 3x+1
y - 1 = 3x+3xy
y - 1 = 3x(1+y)
y - 1 / 1+y = 3x
y - 1 / 3(1+y) = x
x = y - 1 / 3(1+y)
  y-1
x=_____
  3(y+1)

  2x+3
3.y=____    [x]
  x-1

y(x - 1) = 2x+3
xy - y = 2x+3
xy - 2x = y+3
x(y - 2) = y+3
x = y+3 / y - 2
  y+3
3.x=___
  y-2



2006-11-12 17:28:03 補充:
由第一部跳到第二部,因為兩邊都是分數所以將分母乘上去,即「交叉相乘」  3x 1 2.y=____    [x]  1-3xy(1 - 3x) = 3x 1  2x 33.y=____    [x]  x-1y(x - 1) = 2x 3
2006-11-13 1:32 am
1. 2xy+3=2x-y  [x]

y+3 = 2x - 2xy

y+3 = x(2 - 2y)

y+3 / 2 - 2y = x

y+3 / 2(1-y) = x

x = y+3 / 2(1-y)

ans:
  y+3
x=_____
  2(1-y)



  3x+1 
2.y=____    [x]
  1-3x


y(1 - 3x) = 3x+1

y - 3xy = 3x+1

y - 1 = 3x+3xy

y - 1 = 3x(1+y)

y - 1 / 1+y = 3x

y - 1 / 3(1+y) = x

x = y - 1 / 3(1+y)

  y-1
x=_____
  3(y+1)



  2x+3
3.y=____    [x]
  x-1


y(x - 1) = 2x+3

xy - y = 2x+3

xy - 2x = y+3

x(y - 2) = y+3

x = y+3 / y - 2

  y+3
3.x=___
  y-2
2006-11-13 1:20 am
1. 2xy+3=2x-y  [x]
2xy-2x=-3-y
2x(y-1)=-3-y
2x=-3-y/y-1
x=-3-y/2(y-1)

  3x+1 
2.y=____    [x]
  1-3x
y(1-3x)=3x+1
y(1-3x)-3x=1
y-3x(y-1)=1
y-1=3x(y-1)
x=y-1/3(y+1)

  2x+3
3.y=____    [x]
  x-1
y(x-1)=2x+3
y(x-1)-2x=3
x(y-2)-y=3
x=3+y/y-2
參考: me


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