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2006-11-12 10:18 pm
7k-(9k-16)=14-(19-k)

回答 (7)

2006-11-12 10:25 pm
✔ 最佳答案
7k-(9k-16)=14-(19-k)

7k-9k+16=14-19+k (拆括號,負負得正。)

7k-9k-k=14-19-16

-3k=-21

k=-7
2006-11-12 10:48 pm
7k-(9k-16)=14-(19-k)
7k-9k 16=14-19 k
7k-9k-k=14-19-16
-3k = -21
k = 7
2006-11-12 10:29 pm
7k-(9k-16)=14-(19-k)
7k-9k+16=14-19+k
7k-9k-k=14-19-16
-3k=-21
k=?(自己計啦)
參考: 記住:負負得正,正正得正,負正得負,正負得負
2006-11-12 10:23 pm
7k-(9k-16) = 14-(19-k)
7k-9k+16 = 14-19+k
16-14+19 = k-7k+9k
21 = 3k
k = 7
2006-11-12 10:23 pm
7k-(9k-16)=14-(19-k)
7k-9k+16=14-19+k
-2k-k=-5-16
-3k=-21
k=7
2006-11-12 10:22 pm
7k-(9k-16)=14-(19-k)
7k-9k+16=14-19+k
7k-9k-k=14-16
-3k = -2
k = 2/3

2006-11-12 14:23:42 補充:
我錯左,不過樓上都錯左!!我修正,要最佳回答!!!7k-(9k-16)=14-(19-k)7k-9k 16=14-19 k7k-9k-k=14-19-16-3k = -21k = 7
2006-11-12 10:22 pm
7k-(9k-16)=14-(19-k)

7k-9k+16=14-19+k

7k-9k-k=14-19-16

-3k=-21

k=-7

2006-11-12 20:04:44 補充:
sorry,打多左個負號,應為k=7


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