我想問一條數呀
回答 (4)
2006-11-12 7:25 am
✔ 最佳答案
16a^2-9=4^2a^2-3^2
=(4a)^2-3^2
=(4a-3)(4a+3)
*a^2-b^2=(a-b)(a+b)
參考: Me
2006-11-12 7:59 am
16a2次方-9
=(4a)^2-3^2
=(4a+3)(4a-3)
=(4a)^2-3^2
=(4a+3)(4a-3)
2006-11-12 7:27 am
faterization??
if yes, then
16a^2-9
=(4a)^2-(3)^2
=(4a+3)(4a-3)
if yes, then
16a^2-9
=(4a)^2-(3)^2
=(4a+3)(4a-3)
2006-11-12 7:25 am
16a2次方-9
= (4a)2次方 - 3嘅2次方 --- 恒等式
= ( 4a + 3 )( 4a - 3 )
= (4a)2次方 - 3嘅2次方 --- 恒等式
= ( 4a + 3 )( 4a - 3 )
收錄日期: 2021-04-12 22:51:07
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https://hk.answers.yahoo.com/question/index?qid=20061111000051KK06108