3[7-4(c-2)]=41

2006-11-11 7:06 pm
Maths question!!!Quickly and right one is the best answer!!!So easy!!!Give the知識分數 to you!!

回答 (8)

2006-11-11 7:10 pm
✔ 最佳答案
3[7-4(c-2)]=41

3(7-4c+8)=41
21-12c+24=41
-12c=41-21-24
-12c=-4
c=1/3
2006-11-11 8:01 pm
3[7-4(c-2)]=41
21-[12(c-2)]=41
21-(12c-24)=41
21-12c+24=41
45 -12c=41
12c=4
c=1/3
參考: 數學能手Me
2006-11-11 7:51 pm
3[7-4(c-2)]=41
3(7-4c+8)=41
3(15-4c)=41
45-12c=41
4=12c
12c=4
c=1/3
2006-11-11 7:36 pm
0.33333333............
2006-11-11 7:14 pm
3[7-4c+8]=41
21-12c+24=41
45-12c=41
-12c=41-45
-12c=-4
-12c÷12=-4÷-12
c=三分之一
2006-11-11 7:13 pm
3[7-(4c-8)]=41
7-4c+8=41/3
-4c=(41/3)-15
c= 1/3
2006-11-11 7:13 pm
3[7-4(c-2)]=41
3[7-4c-8]=41
21-12c-56=41
21-12c-56+56=41+56
21-12c+21=97+21
12c=118
c=95/6(9又6分5)
2006-11-11 7:12 pm
1/3
1 over 3
3份之1
囉~~~


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