Math F.1
回答 (4)
=5-4y^2-5y+y^2-3
=5-3-4y^2+y^2-5y
=2-3y^2-5y
=2-5y-3y^2
參考: me
=5-4y^2-5y+y^2+3
= -3y^2-5y+8
=(8-3y)(y-1)
(5-4y^2)-(5y-y^2+3)
=5-4y^2-5y+y^2+3
=-5y^2-5y+8
參考: me
收錄日期: 2021-04-13 16:09:50
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