6^4 x 9^2 x (1/3)^5,,可唔可以用第2個方法..?

2006-11-10 2:26 am
6^4 x 9^2 x (1/3)^5,,可唔可以用第2個方法..?

6^4 x 9^2 x (1/3)^5
=1296 x 81 x 5/243
= 2160..
但可唔可以唔乘晒出尼..

可唔可以通左佢地個coefficient變成都係3...
但係點通呀??

回答 (3)

2006-11-10 2:41 am
✔ 最佳答案
你計錯數wor
三分一既五次方係 1/243

6^4 x 9^2 x (1/3)^5
= 1296 x 81 x 1/243
= 432

另外個方法:

6^4 x 9^2 x (1/3)^5
= (2x3)^4 x (3^2)^2 x (3^-1)^5
= 2^4 x 3^4 x 3^4 x 3^-5
= 16 x 3^(4+4-5)
= 16 x 3^3
= 16 x 27
= 432
參考: 自己
2006-11-10 2:35 am
6^4×9²×(1/3)^5
=(3×2)^4×(3×3)²×1^5/3^5
=3^4×2^4×3²×3²×1/3^5
=3^(4+2+2-5)×2^4
=3³×2^4
=27×16
=432
2006-11-10 2:32 am
6^4 x 9^2 x (1/3)^5

=(3*2)^4 * (3^2)^2 * 1/(3^5)

=3^4 * 3^4 * 1/(3^5) * 2*4

=3^(4+4-5) * 16

=3^3 * 16

=432


收錄日期: 2021-04-12 22:26:57
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061109000051KK02861

檢視 Wayback Machine 備份