21.A shopkeeper bought a table at $460, 6 chairs at $90 each .He sold the table at a profit of 30% and the chairs at a loss of$5%.
a)Find the profit from the table.
b)Find the loss from the chairs.
c)Find the total cost for the table and chairs.
d)Find the overall profit percent.
maths
2006-11-08 6:05 am
回答 (3)
2006-11-08 6:18 am
✔ 最佳答案
a, profit from the table= $460 x 130% - $460
= $598 - $460
= $138
b, loss from the chairs
= $90 x 6 - $90 x 6 x 95%
= $540 - $513
= $27
c, total cost for the table and chairs
= $598 + $513
= $1111
d, overall profit percent
= [$1111 - ($460 + $90 x 6 ) ] x 100% / $460 + $90 x 6
= 11.1%
太多年無計過數 la, 希望無計錯數la
haha
2006-11-08 6:13 am
a)460*(1+30%)
=$552
b)90*6*(1-5%)
=$513
c)460+6*90
=$1000
d)(552+513-1000)/1000
=6.5%
+分 plx
=$552
b)90*6*(1-5%)
=$513
c)460+6*90
=$1000
d)(552+513-1000)/1000
=6.5%
+分 plx
2006-11-08 6:13 am
Profit from table = $460 x 30% = $138
Loss from chairs = $90 x 6 x 5% = ($27)
Total cost = $460 + ($90 x 6) = $1,000
Effective profit rate = ($1,111-$1,000)/$1,000 =11%
OK
Loss from chairs = $90 x 6 x 5% = ($27)
Total cost = $460 + ($90 x 6) = $1,000
Effective profit rate = ($1,111-$1,000)/$1,000 =11%
OK
收錄日期: 2021-04-23 15:58:08
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