F=g-1/g
[g]
Changing the subject of a formula
2006-11-08 12:31 am
回答 (5)
2006-11-08 12:36 am
✔ 最佳答案
F=1-g分之1-Fg=1
g=-F分之1
2006-11-07 16:39:07 補充：
SORRYFg=g-1Fg-g=-1g(F-1)=-1g=1-F分之1
2006-11-07 16:40:48 補充：
第一次回答是錯的補答才是正確ANS
2006-11-08 1:14 am
The answer should be
F=(g-1)/g
Fg = g-1
1 = g - Fg
1 = g (1-F)
g = 1/(1-F)
F=(g-1)/g
Fg = g-1
1 = g - Fg
1 = g (1-F)
g = 1/(1-F)
參考: myself
2006-11-08 12:59 am
What do you mean?
You mean F=g-1/g or F=(g-1)/g?
Situation 1
F=g-1/g
F=(g^2-1)/g
Fg=g^2-1
g^2-Fg-1=0
g=[F士(F^2+4)^(1/2)]/2
Situation 2:
F=(g-1)/g
F=1-1/g
F-1=-1/g
1-F=1/g
g=1/(1-F)
You mean F=g-1/g or F=(g-1)/g?
Situation 1
F=g-1/g
F=(g^2-1)/g
Fg=g^2-1
g^2-Fg-1=0
g=[F士(F^2+4)^(1/2)]/2
Situation 2:
F=(g-1)/g
F=1-1/g
F-1=-1/g
1-F=1/g
g=1/(1-F)
2006-11-08 12:46 am
Actually what do you mean?
Possibility 1:
F = (g-1)/g
Fg = g-1
g(F-1) = -1
Therefore g = -1/(F-1)
g = 1/(1-F)
Do you mean this?
If no, do you mean F=g-1/g
Fg = g^2 -1
g^2-Fg-1 = 0
If you want to solve g, you must use quadratic equation
Possibility 1:
F = (g-1)/g
Fg = g-1
g(F-1) = -1
Therefore g = -1/(F-1)
g = 1/(1-F)
Do you mean this?
If no, do you mean F=g-1/g
Fg = g^2 -1
g^2-Fg-1 = 0
If you want to solve g, you must use quadratic equation
2006-11-08 12:37 am
F=g-1/g
Fg = g-1
1 = g-Fg
1 = g (1-F)
g = 1/(1-F)
Fg = g-1
1 = g-Fg
1 = g (1-F)
g = 1/(1-F)
收錄日期: 2021-04-12 20:15:17
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https://hk.answers.yahoo.com/question/index?qid=20061107000051KK01999