Factorize 64x^3 － 27y^3
列明步驟
Factorize 64x^3 － 27y^3
2006-11-07 8:34 am
回答 (2)
2006-11-07 7:41 pm
since a^3-b^3=(a-b)(a^2+ab+b^2)
64x^3-27y^3
=(4x)^3-(3y)^3
=(4x-3y)(16x^2+12xy+9y^2)
64x^3-27y^3
=(4x)^3-(3y)^3
=(4x-3y)(16x^2+12xy+9y^2)
2006-11-07 5:28 pm
because
a^3 - b^3 = (a - b)(a^2 + ab + b^2)
so
64x^3-27y^3
=(4x)^3-(3y)^3
=(4x-3y)[(4x)^2+(4x)(3y)+(3y)^2]
=(4x-3y)(16x^2+12xy+9y^2)
a^3 - b^3 = (a - b)(a^2 + ab + b^2)
so
64x^3-27y^3
=(4x)^3-(3y)^3
=(4x-3y)[(4x)^2+(4x)(3y)+(3y)^2]
=(4x-3y)(16x^2+12xy+9y^2)
收錄日期: 2021-04-12 20:28:07
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061107000051KK00147