又一條數學題.........

2006-11-07 7:05 am
若 p = 2 及 q = -3時以下的數式的值

(p^ - 4pq + q^) - (p^ + 4pq - q^)

註: ^ = 2次方

唔該哂!

回答 (6)

2006-11-07 7:11 am
✔ 最佳答案
(p^ - 4pq + q^) - (p^ + 4pq - q^)
=p^ - 4pq + q^ - p^ - 4pq + q^
= -8pq+ 2q^
= -8 X 2 X -3 + 2 X 9
=48 + 18
=66
2006-11-07 7:31 am
因式分解:

(p^ - 4pq + q^) - (p^ + 4pq - q^)

=[2^ - ( 4 )( 2 )( -3 ) + 3 ^ ] - [ 2^ + ( 4 )( 2 )( 3 )- 3^ ]

=[ 4 - ( - 24 ) + 9 ] - [ 4 + 24 - 9 ]

=[ 4 + 24 + 9 ] + [ 4 - 24 + 9 ] <------[[後面要抽符號]]

=( 2 + 9 )^ +( 2 - 9 )^


答可能係: ( 2 + 9 ) ^ +( 2 - 9 ) ^


普通的:
(p^ - 4pq + q^) - (p^ + 4pq - q^)

=[2^ - ( 4 )( 2 )( -3 ) + 3 ^ ] - [ 2^ + ( 4 )( 2 )( 3 )- 3^ ]

=[ 4 - ( - 24 ) + 9 ] - [ 4 + 24 - 9 ]

= 4 + 24 + 9 - 4 - 24 + 9

= 18
2006-11-07 7:18 am
(p^ - 4pq + q^) - (p^ + 4pq - q^)
=p^ - 4pq + q^ - p^ - 4pq + q^
= -8pq+ 2q^
= -8 X 2 X -3 + 2 X 9
=48 + 18
=66
2006-11-07 7:12 am
答案66...將d數代入式...得..37+29....答案66
2006-11-07 7:12 am
(p^ - 4pq + q^) - (p^ + 4pq - q^)
即是:
[(2)^-4(2)(-3)+(-3)^]-[(2)^+4(2)(-3)-(-3)^]
=4+24+9-4-24+9
=18
2006-11-07 7:09 am
-8pq=(-8)(2)(-3)=48

2006-11-06 23:17:34 補充:
算漏了 +2q^ 一項正確答案 66!


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