✔ 最佳答案
X = [-b + sqrt(b^2-4aC)]/(2a) or
X = [-b - sqrt(b^2-4aC)]/(2a)
2006-11-06 22:30:27 補充:
aX^2 bX C = 0(aX)^2 b(aX) aC = 0(aX)^2 b(aX) (b/2)^2 - (b/2)^2 aC = 0(aX b/2)^2 - (b/2)^2 aC = 0(aX b/2)^2 = (b/2)^2 - aC
2006-11-06 22:30:53 補充:
aX b/2 = sqrt((b/2)^2 - aC) or aX b/2 = sqrt((b/2)^2 - aC) X = -b/2a sqrt((b/2)^2 - aC)/a or X = -b/2a sqrt((b/2)^2 - aC)/a X = [-b 2sqrt((b/2)^2 - aC)]/(2a) or X = [-b 2sqrt((b/2)^2 - aC)]/(2a)X = [-b sqrt(b^2 - 4aC)]/(2a) or X = [-b sqrt(b^2 - 4aC)]/(2a)
2006-11-06 22:32:30 補充:
aX^2 bX C = 0(aX)^2 b(aX) aC = 0(aX)^2 b(aX) (b/2)^2 - (b/2)^2 aC = 0(aX b/2)^2 - (b/2)^2 aC = 0(aX b/2)^2 = (b/2)^2 - aC
2006-11-06 22:33:11 補充:
aX b/2 = sqrt((b/2)^2 - aC) or aX b/2 = sqrt((b/2)^2 - aC) X = -b/2a sqrt((b/2)^2 - aC)/a or X = -b/2a sqrt((b/2)^2 - aC)/a X = [-b 2sqrt((b/2)^2 - aC)]/(2a) or X = [-b 2sqrt((b/2)^2 - aC)]/(2a)X = [-b sqrt(b^2 - 4aC)]/(2a) or X = [-b sqrt(b^2 - 4aC)]/(2a)