px^2 + 5x 恆等 qx + r ,, p=?,,q=?,,r=??
this is identity....
so difficult...
px^2 + 5x 恆等 qx + r ,, p=?,,q=?,,r=??
2006-11-06 9:29 pm
回答 (2)
2006-11-06 9:32 pm
✔ 最佳答案
因為 px^2 + 5x 恆等 qx + r 所以對 conefficient 就可以..so p = 0 (對 x^2)
q = 5 (對 x)
r = 0 (對 constant)
2006-11-06 9:36 pm
p = [(q-5)x + r ]/ x^2
q = (px^2 + 5x - r) / x
r = px^2 + (5-q)x
q = (px^2 + 5x - r) / x
r = px^2 + (5-q)x
收錄日期: 2021-04-12 22:26:45
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061106000051KK01369