開平方根(x^2n y^6n)
幫幫手= =
中三math問題
2006-11-06 2:23 am
回答 (3)
2006-11-06 2:29 am
✔ 最佳答案
x^2n y^6n=(x^n+n)(y^3n+3n)
=(x^n)(x^n)(y^3n)(y^3n)
So the square root of x^2n y^6n
=square root of 〔(x^n)(x^n)(y^3n)(y^3n)〕
=x^n y^3n
2006-11-06 2:42 am
x^2n y^6n
=(x^n+n)(y^3n+3n)
=(x^n)(x^n)(y^3n)(y^3n)
平方根(x^2n y^6n)
=(x^n)(y^3n)
=(x^n+n)(y^3n+3n)
=(x^n)(x^n)(y^3n)(y^3n)
平方根(x^2n y^6n)
=(x^n)(y^3n)
2006-11-06 2:31 am
x^ny^3n
收錄日期: 2021-04-12 18:05:45
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061105000051KK04393