1.)ah+a-h+1=0 [h]
2.)T=2d-s/s-3d [d]
THX.......
更新1:
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FORM2數學......急
2006-11-05 10:01 pm
Make the letter in the brackets the subject of each of the following formulae.
1.)ah+a-h+1=0 [h]
2.)T=2d-s/s-3d [d]
THX.......
1.)ah+a-h+1=0 [h]
2.)T=2d-s/s-3d [d]
THX.......
回答 (4)
2006-11-05 10:05 pm
✔ 最佳答案
ah+a-h+1=0(a-1)h=-(a+1)
h = -(a+1)/(a-1)
T=2d-s/s-3d
(s-3d)T=2d-s
sT-3dT=2d-s
(2-3T)d=sT+s
d=s(T+1)/(2-3T)
2006-11-05 14:07:06 補充：
SORRY.. 打錯左T=2d-s/s-3d(s-3d)T=2d-ssT-3dT=2d-s(2+3T)d=sT+sd=s(T+1)/(2+3T)
2006-11-05 10:56 pm
1.)
ah+a-h+1=0
-h=-ah-a-1
h=ah+a+1
======
2.)
T=2d-s/s-3d
(s-3d)T=2d-s
(s-3d)T+s/2=d
d=(s-3d)T+s/2
=========
ah+a-h+1=0
-h=-ah-a-1
h=ah+a+1
======
2.)
T=2d-s/s-3d
(s-3d)T=2d-s
(s-3d)T+s/2=d
d=(s-3d)T+s/2
=========
2006-11-05 10:13 pm
1) ah+a-h+1=0
h(a-1)=-a-1
h = -(a+1)/(a-1)
2) T=2d-s/s-2d
Ts-2Td=2d-s
2d+2Td=Ts+s
d(2+2T)=s(T+1)
d=s(T+1)/2(1+T)
d=s/2
2006-11-05 14:16:38 補充：
睇錯題目,,2) T=2d-s/s-3dTs-3dT=2d-sTs s=2d 3dTs(T 1)=d(2 3T)s(T 1)/2 3T=dd=s(T 1)/2 3T
2006-11-05 14:17:50 補充：
睇錯題目,,2) T=2d-s/s-3dTs-3dT=2d-sTs+s=2d+3dTs(T+1)=d(2+3T)s(T+1)/2+3T=dd=s(T+1)/2+3T
h(a-1)=-a-1
h = -(a+1)/(a-1)
2) T=2d-s/s-2d
Ts-2Td=2d-s
2d+2Td=Ts+s
d(2+2T)=s(T+1)
d=s(T+1)/2(1+T)
d=s/2
2006-11-05 14:16:38 補充：
睇錯題目,,2) T=2d-s/s-3dTs-3dT=2d-sTs s=2d 3dTs(T 1)=d(2 3T)s(T 1)/2 3T=dd=s(T 1)/2 3T
2006-11-05 14:17:50 補充：
睇錯題目,,2) T=2d-s/s-3dTs-3dT=2d-sTs+s=2d+3dTs(T+1)=d(2+3T)s(T+1)/2+3T=dd=s(T+1)/2+3T
2006-11-05 10:09 pm
1.) ah+a-h+1=0
ah-h+a+1=0
h(a-1)=-(a+1)
h=-(a+1)/a-1
2.) T=2d-s/s-3d
T(s-3d)=2d-s
Ts-3dT=2d-s
Ts+s=2d+3dT
s(T+1)=d(2+3T)
s(T+1)/s+3T=d
d=s(T+1)/s+3T
ah-h+a+1=0
h(a-1)=-(a+1)
h=-(a+1)/a-1
2.) T=2d-s/s-3d
T(s-3d)=2d-s
Ts-3dT=2d-s
Ts+s=2d+3dT
s(T+1)=d(2+3T)
s(T+1)/s+3T=d
d=s(T+1)/s+3T
收錄日期: 2021-05-02 19:05:53
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061105000051KK02454