Maths questions:

2006-11-05 7:58 pm
Can you find out the mistakes of these steps????
1.)A/3=9+8(A-3/4)
A/3=17(A-3/4)
12*A/3=(17A-51/4)*12
4A=204A-153
A4-204A=-153
-200A/-200=-153/-200
A=153/200

2.)1-2[3-(X/2-1)]=X/4+1
-1(3-X/2-1)=X/4+1
4*(31+X/2-1)=(X/4+1)*4
-12+2X-4=X+4
2X-X=12+4+4
X=20
This answer of this sum in my book is 10 and2/3..
but i believe This answer  is also correct....

回答 (1)

2006-11-05 8:14 pm
✔ 最佳答案
1.)A/3=9+8(A-3/4)之後
A/3=17(A-3/4)呢部已經錯...先乘除後加減...拆左括號先...
A/3=9+8(A-3/4) 之後should be A/3= 9+8A-6...自己計落去la...

2.) 1-2[3-(X/2-1)]=X/4+1之後...-1(3-X/2-1)=X/4+1一樣同上面錯法la...
拆左細括號先, 然後中括號...
1-2[3-(X/2-1)]=X/4+1之後 should be -1-2(3-X/2-1)
再之後-1-2(2-X/2)=x/4+1
-1-4+x/2=x/4+1....之後自己計...


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