1. ( x + 1) ( x - 1 ) - ( x + 1 ) ( 2x + 1 )
2. 4 ( x + 1 )ニ次方 - 9
一元ニ次方程....
2006-11-05 6:59 pm
回答 (2)
2006-11-05 7:06 pm
✔ 最佳答案
1. ( x + 1) ( x - 1 ) - ( x + 1 ) ( 2x + 1 )= ( x + 1) (x -1 -2x - 1)
= - ( x + 1) ( x + 2 )
2. 4 ( x + 1 )ニ次方 - 9
= [2 ( x + 1 )] ニ次方 - 3 ニ次方
= (2x+2+3)(2x+2-3)
= (2x+5)(2x-1)
參考: 自己
2006-11-05 7:08 pm
( x + 1) ( x - 1 ) - ( x + 1 ) ( 2x + 1 )
=(x+1)(x-1-2x+1)
=(x+1)(-x)
=(x+1)(x-1-2x+1)
=(x+1)(-x)
收錄日期: 2021-04-12 22:30:49
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https://hk.answers.yahoo.com/question/index?qid=20061105000051KK01311