If the quadratic equation 4x^2-gx+15=0 has two distinct real roots which of the following are the possible values of g?
solution:
Because the quadratic equation 4x^2-gx+15=0 has two distinct real roots
∴ △﹥0
4x^2-gx+15﹥0
(-g)^2-4(4)(15)﹥0
g^2-240﹥0
g^2﹥240
g﹥±15.49...
F4 Maths...我有咩錯!
2006-11-05 3:13 am
回答 (1)
2006-11-07 5:36 am
✔ 最佳答案
solution:Because the quadratic equation 4x^2-gx+15=0 has two distinct real roots
∴ △﹥0
4x^2-gx+15﹥0
(-g)^2-4(4)(15)﹥0
g^2-240﹥0
g^2﹥240
g﹥±15.49...
4x^2-gx+15﹥0 這句是wrong 的
g^2﹥240
(g+15.49)(g-15.49)>0
g<-15.49 or g>15.49
收錄日期: 2021-04-23 15:50:53
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https://hk.answers.yahoo.com/question/index?qid=20061104000051KK04172