MATHs

2006-11-05 2:42 am

1/x-4-x/(4-x)(4-x) ----------------------How to do?

回答 (4)

2006-11-05 4:14 am

✔ 最佳答案

1/(x-4)-x/(4-x)(4-x)
= x-4/(x-4)^2–x/(x-4)^2
= x-4/(x-4)^2–x/(x-4)^2
= x-4-x/(x-4)^2
= -4/ (x-4)^2

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2006-11-10 5:31 am

答案和最快答這完全一樣，點解會選較慢的一位為最佳回答？？

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2006-11-05 6:57 am

1/(x-4)-x/(4-x)(4-x)
= x-4/(x-4)^2–x/(x-4)^2
= x-4/(x-4)^2–x/(x-4)^2
= x-4-x/(x-4)^2
= -4/ (x-4)^2

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2006-11-05 2:48 am

1/(x-4)-x/(4-x)(4-x)
= (x-4)/(x-4)^2 – x/(x-4)^2
= (x-4)/(x-4)^2 – x/(x-4)^2
= [(x-4)-x]/(x-4)^2
= -4/ (x-4)^2

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