MATHs
回答 (4)
2006-11-05 4:14 am
✔ 最佳答案
1/(x-4)-x/(4-x)(4-x)= x-4/(x-4)^2–x/(x-4)^2
= x-4/(x-4)^2–x/(x-4)^2
= x-4-x/(x-4)^2
= -4/ (x-4)^2
2006-11-10 5:31 am
答案和最快答這完全一樣，點解會選較慢的一位為最佳回答？？
2006-11-05 6:57 am
1/(x-4)-x/(4-x)(4-x)
= x-4/(x-4)^2–x/(x-4)^2
= x-4/(x-4)^2–x/(x-4)^2
= x-4-x/(x-4)^2
= -4/ (x-4)^2
= x-4/(x-4)^2–x/(x-4)^2
= x-4/(x-4)^2–x/(x-4)^2
= x-4-x/(x-4)^2
= -4/ (x-4)^2
2006-11-05 2:48 am
1/(x-4)-x/(4-x)(4-x)
= (x-4)/(x-4)^2 – x/(x-4)^2
= (x-4)/(x-4)^2 – x/(x-4)^2
= [(x-4)-x]/(x-4)^2
= -4/ (x-4)^2
= (x-4)/(x-4)^2 – x/(x-4)^2
= (x-4)/(x-4)^2 – x/(x-4)^2
= [(x-4)-x]/(x-4)^2
= -4/ (x-4)^2
收錄日期: 2021-05-02 19:05:36
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061104000051KK03943