simply the following expreession
a)(6a+d)-(2a-d)
b) 2 2
(4x -5x+7)- 2x -6x)
multiply the following expressions by the method of expansion
a)2c(a+2b)
b)-4(1+5a+a SQUARE)
c)(x+1)(x SQUARE+x+1)
有d功課唔色.......(polynomials)
2006-11-03 8:30 pm
回答 (4)
2006-11-03 8:51 pm
✔ 最佳答案
a.=6a+d-2a+d
=4a+2d
b
=4x-5x+7-2x+6x
=3x+7
a
=2ca+4cb
b
=-4-20a-4a^2
c
=x^3+x^2+x+x^2+x+1
=x^3+2x^2+2x+1
2006-11-03 10:06 pm
a.6a+d)-(2a-d)
=6a+d-2a+d
=4a+2d
b.2 2
(4x -5x+7)- 2x -6x)
=4x-5x+7-2x+6x
=3x+7
multiply the following expressions by the method of expansion
a2c(a+2b)
=2ca+4cb
b)-4(1+5a+a SQUARE)
=-4-20a-4a^2
c)(x+1)(x SQUARE+x+1)
=x^3+x^2+x+x^2+x+1
=x^3+2x^2+2x+1
=6a+d-2a+d
=4a+2d
b.2 2
(4x -5x+7)- 2x -6x)
=4x-5x+7-2x+6x
=3x+7
multiply the following expressions by the method of expansion
a2c(a+2b)
=2ca+4cb
b)-4(1+5a+a SQUARE)
=-4-20a-4a^2
c)(x+1)(x SQUARE+x+1)
=x^3+x^2+x+x^2+x+1
=x^3+2x^2+2x+1
參考: thx.........
2006-11-03 9:18 pm
請自己找補習老師，不要在此問功課，難道你上課沒有聽書？？？
如此簡單的問題，在你的課本例題一定可以解答得到你的！
(a) 6a+d-2a+d
=4a+2d
=2(2a+d)
請參考一題,其他自己回答
如此簡單的問題，在你的課本例題一定可以解答得到你的！
(a) 6a+d-2a+d
=4a+2d
=2(2a+d)
請參考一題,其他自己回答
2006-11-03 9:02 pm
a) (6a+d)-(2a-d)
=6a+d-2a+d
=4a+2d
=2(2a+d)
b) 2 2
(4x -5x+7)- 2x -6x)
唔明你寫什麼
a)2c(a+2b)
=2ca+4bc
b)-4(1+5a+a SQUARE)
= -4-20a-4aSQ
c)(x+1)(x SQUARE+x+1)
= x CUBE + x SQ + x SQ + x + x + 1
= x CUBE + 2x SQ + x + 1
唔知有無計錯, 十幾年無計過
2006-11-03 13:05:02 補充：
更正c)(x+1)(x SQUARE+x+1)= x CUBE + x SQ + x SQ + x + x + 1= x CUBE + 2x SQ + 2x + 1
=6a+d-2a+d
=4a+2d
=2(2a+d)
b) 2 2
(4x -5x+7)- 2x -6x)
唔明你寫什麼
a)2c(a+2b)
=2ca+4bc
b)-4(1+5a+a SQUARE)
= -4-20a-4aSQ
c)(x+1)(x SQUARE+x+1)
= x CUBE + x SQ + x SQ + x + x + 1
= x CUBE + 2x SQ + x + 1
唔知有無計錯, 十幾年無計過
2006-11-03 13:05:02 補充：
更正c)(x+1)(x SQUARE+x+1)= x CUBE + x SQ + x SQ + x + x + 1= x CUBE + 2x SQ + 2x + 1
收錄日期: 2021-04-13 13:30:15
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