20+b=bx120%
跟住ge步驟係點計??
數學問題.....plz help
2006-11-03 7:41 pm
回答 (4)
2006-11-03 7:53 pm
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20+b=1.2b
20=1.2b-b
20=(1.2-1)b
20=0.2b
b=100
20+b=1.2b
20=1.2b-b
20=(1.2-1)b
20=0.2b
b=100
2006-11-03 7:45 pm
20+b=120%*b
20+b=1.2b
20=1.2b-b
20=b(1.2-1)
20=0.2B
b=20/0.2
b=100
20+b=1.2b
20=1.2b-b
20=b(1.2-1)
20=0.2B
b=20/0.2
b=100
2006-11-03 7:44 pm
as you know that 120%=1.2
so 20+b = 1.2b
0.2b = 20 (moving the b to one side)
thus b = 100
so 20+b = 1.2b
0.2b = 20 (moving the b to one side)
thus b = 100
參考: myself
2006-11-03 7:43 pm
20+b=1.2b
20=1.2b-b
20=0.2b
b=100
20=1.2b-b
20=0.2b
b=100
收錄日期: 2021-04-12 18:22:34
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061103000051KK00975