唔該呀,一d多項式題目唔識呀!!

(m+1)(m+2)(m+3)

=mxmxm+1x2x3

=m3次方+6

我計做咁喎....!!

(m+1)(m+2)(m+3)
=(m^2+2m+m+2)(m+3)
=(m^2+3m+2)(m+3)
=m^3+3m^2+3m^2+9m+2m+6
=m^3+6m^2+11m+6

Because of the distribution law of multplication
因為乘法分配性質
(a+b)(c+d)
=a(c+d)+b(c+d)
=ac+ad+bc+bd
We use this method to simplify (m+1)(m+2)(m+3).
我們用這個方法去簡化(m+1)(m+2)(m+3)

2006-11-02 21:17:53 補充：
唔好意思乘法分配性質應該是distributive law of multiplication一樓那位:你做的方法極之不合理由於加法交換性質m十1=1十m如果照你咁計(錯誤示範!!!)(m十1)(m十2)=m^2 2則(1十m)(m十2)亦得相同答案(1十m)(m十2)=m十2m=3m兩者已經不相同所以閣下的方法是錯的!!!

(m+1)(m+2)(m+3)
=(m^2+3m+2)(m+3)
= m^3+3m^2+2m+3m^2+9m+6
= m^3+6m^2+11m+6
PS--^ = 次方

(m+1)(m+2)(m+3)
=(m^2+m+2m+2)(m+3)
=(m^2+3m+2)(m+3)
=m^3+3m^2+2m+3m^2+9m+6
=m^3+6m^2+11m+6