中一方程 急(請睇清楚題目)
回答 (7)
✔ 最佳答案
(3(x+1)/2)*3-5/6=(x-2)/3
3(3x+3)/6-5/6=-(x-2)/3
(9x+9)/6-5/6=-(x-2)/3
(9x+9-5)/6=-(x-2)/3
(9x+4)/2=-x+2
9x+4=-2x+4
9x+2x=0
11x=0
x=0
3/2(x+1)-5/6=-1/3(x- 2)
6(3/2(x+1)-5/6)=6(-1/3(x- 2) )
9(x+1)-5=-2(x-2)
9x+9-5=-2x+4
9x+4=-2x+4
9x=-2x
11x=0
x=0
3/2(x+1)-5/6=-1/3(x-2)
9/2(x+1)-5/2=-(x-2)
9(x+1)-5=-2(x-2)
9x+9-5=-2x+4
11x+4=4
11x=0
x=0
3/2(x+1)-5/6=-1/3(x-2)
3/2x+3/2-5/6=-1/3x+2/3
3/2x+1/3x=2/3-1又1/2+5/6
1又5/6x=0
x=0除1又5/6
x=無意義
3/2(x+1)-5/6=-1/3(x-2)
(x+1)-5/6=-1/3(x-2)+3/2(通分母)
(x+1)-5/6=7/6(x-2)
(x+1)-5/6=7/6(x-2)+2
(x+1)-5/6=7/6x
(x+1)=7/6x+5/6
(x+1)=12/6+x
x=1又12/6x
x=1又12/6
唔知對不對= =
3/2(x+1)-5/6=-1/3(x-2)
[3/2(x+1)-5/6]x6=[-1/3(x-2)]X6
9x+9-5=-2x+4
11x=0
x=0
收錄日期: 2021-04-13 13:49:56
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