例如這個題目
(2x-1)(x-2)=x(2x-4)-(x-2)
LHS=(2x-1)(x-2)
=2X(X-2)-(X-2)
=2X^2-4X-X+2
=2X^2-5X+2
我不明為什麼
LHS=(2x-1)(x-2)
=2X(X-2)-(X-2)
請用一些文字等等去解釋為什麼=(2x-1)(x-2)展開後是2X(X-2)-(X-2)
解釋以下恆等式
2006-11-03 2:28 am
回答 (2)
2006-11-03 2:37 am
✔ 最佳答案
(2x-1)(x-2)假如(x-2)=c
(2x-1)(x-2) = (2x-1)C=C(2x-1)
展開
=2xC-1C
=2x(x-2)-1(x-2)
=2x(x-2)-x(x-2)
2006-11-03 2:37 am
(2x-1)(x-2)
=2x(x-2)-1(x-2)
=2x(x-2)-(x-2)
=2x(x-2)-1(x-2)
=2x(x-2)-(x-2)
收錄日期: 2021-04-13 14:49:14
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061102000051KK02908