有d數我唔係好明...計左十幾廿次都錯..所以希望有人指點一下..
thank you!!!!
請列步驟:
1. st - 8s - 2t+16
2.4xy - 3y + 3z - 4xz
3.xyp - xyq+3p-3q
4.x 2次-x+3x-3
5. x 2次 -2c-2x+cx
6.6p2次+6-4p-9p
7.pa+qa-ra+rb-qb-pb
7條Maths問題??????(中二)
2006-11-03 1:29 am
回答 (7)
2006-11-03 1:40 am
✔ 最佳答案
1.st-8s-2t+16
=s(t-8)-2(t-8)
=(t-8)(s-2)
2.
4xy-3y+3z-4xz
=4xy-3y-4xz+3z
=y(4x-3)-z(4x-3)
=(4x-3)(y-z)
3.
xyp-xyq+3p-3q
=xy(p-q)+3(p-q)
=(p-q)(xy+3)
4.
x²-x+3x-3
=x(x-1)+3(x-1)
=(x-1)(x+3)
5.
x²-2c-2x+cx
=x²+cx-2x-2c
=x(x+c)-2(x+c)
=(x+c)(x-2)
6.
6p²+6-4p-9p
=6p²-4p-9p+6
=2p(3p-2)-3(3p-2)
=(3p-2)(2p-3)
7.
pa+qa-ra+rb-qb-pb
=pa+qa-ra-pb-qb+rb
=a(p+q-r)-b(p+q-r)
=(p+q-r)(a-b)
參考: Calculation
2006-11-03 3:21 am
1.
st-8s-2t+16
=s(t-8)-2(t-8)
=(s-2)(t-8)
2.
4xy-3y+3z-4xz
=y(4x-3)-z(4x-3)
=(4x-3)(y-z)
3.
xyp-xyq+3p-3q
=xy(p-q)+3(p-q)
=(p-q)(xy+3)
4.
x*2-x+3x-3
=x(x-1)+3(x-1)
=(x-1)(x+3)
5.
x*2-2c-2x+cx
=x*2-2x+cx-2c
=x(x-2)+c(x-2)
=(x+c)(x-2)
6.
(6p)*2+6-4p-9p
=(6p)*2-4p-9p+6
=2p(3p-2)-3(3p-2)
=(3p-2)(2p-3)
7.
pa+qa-ra+rb-qb-pb
=a(p+q-r)-b(-r+q+p)
=a(p+q-r)-b(p+q-r)
=(p+q-r)(a-b)
st-8s-2t+16
=s(t-8)-2(t-8)
=(s-2)(t-8)
2.
4xy-3y+3z-4xz
=y(4x-3)-z(4x-3)
=(4x-3)(y-z)
3.
xyp-xyq+3p-3q
=xy(p-q)+3(p-q)
=(p-q)(xy+3)
4.
x*2-x+3x-3
=x(x-1)+3(x-1)
=(x-1)(x+3)
5.
x*2-2c-2x+cx
=x*2-2x+cx-2c
=x(x-2)+c(x-2)
=(x+c)(x-2)
6.
(6p)*2+6-4p-9p
=(6p)*2-4p-9p+6
=2p(3p-2)-3(3p-2)
=(3p-2)(2p-3)
7.
pa+qa-ra+rb-qb-pb
=a(p+q-r)-b(-r+q+p)
=a(p+q-r)-b(p+q-r)
=(p+q-r)(a-b)
2006-11-03 2:06 am
1. st - 8s - 2t+16
=s(t-8)-2(t-8)
=(s-2)(t-8)
2. 4xy - 3y + 3z - 4xz
=4x(y-z)-3(y-z)
=(4x-3)(y-z)
3. xyp - xyq+3p-3q
=xy(p-q)+3(p-q)
=(xy+3)(p-q)
4. x 2次-x+3x-3
=x(x-1)+3(x-1)
=(x+3)(x-1)
5. x 2次 -2c-2x+cx
=x(x+c)-2(c+x)
=(x-2)(x+c)
6. 6p2次+6-4p-9p
=6p^2-13p+6
=(2p-3)(3p-2)
7. pa+qa-ra+rb-qb-pb
=a(p+q-r)+b(r-q-p)
=a(p+q-r)+b(-p-q+r)
=a(p+q-r)+b(-1)(p+q-r)
=a(p+q-r)-b(p+q-r)
=(a-b)(p+q-r)
=s(t-8)-2(t-8)
=(s-2)(t-8)
2. 4xy - 3y + 3z - 4xz
=4x(y-z)-3(y-z)
=(4x-3)(y-z)
3. xyp - xyq+3p-3q
=xy(p-q)+3(p-q)
=(xy+3)(p-q)
4. x 2次-x+3x-3
=x(x-1)+3(x-1)
=(x+3)(x-1)
5. x 2次 -2c-2x+cx
=x(x+c)-2(c+x)
=(x-2)(x+c)
6. 6p2次+6-4p-9p
=6p^2-13p+6
=(2p-3)(3p-2)
7. pa+qa-ra+rb-qb-pb
=a(p+q-r)+b(r-q-p)
=a(p+q-r)+b(-p-q+r)
=a(p+q-r)+b(-1)(p+q-r)
=a(p+q-r)-b(p+q-r)
=(a-b)(p+q-r)
2006-11-03 2:05 am
1. st - 8s - 2t+16
s(t - 8) - 2(t+8)
(s-2)(t-8)
2.4xy - 3y + 3z - 4xz
y(4x - 3) + z(3 - 4x)
y(4x - 3) - z(4x-3)
(y-z)(4x - 3)
3.xyp - xyq+3p-3q
xy(p - q)+3(p-q)
(xy+3)(p - q)
4.x^-x+3x-3
x(x-1)+3(x-1)
(x+3)(x-1)
5. x ^ -2c-2x+cx
x(x-2)+c(x-2)
(x+c)(x-2)
5. x^ -2c-2x+cx
x(x-2)+c(x-2)
(x+c)(x-2)
6.6p^+6-4p-9p
2(3-2p)-3p(3-2p)
(2-3p)(3-2p)
7.pa+qa-ra+rb-qb-pb
a(p+q-r)-b(p+q-r)
(a-b)(p+q-r)
s(t - 8) - 2(t+8)
(s-2)(t-8)
2.4xy - 3y + 3z - 4xz
y(4x - 3) + z(3 - 4x)
y(4x - 3) - z(4x-3)
(y-z)(4x - 3)
3.xyp - xyq+3p-3q
xy(p - q)+3(p-q)
(xy+3)(p - q)
4.x^-x+3x-3
x(x-1)+3(x-1)
(x+3)(x-1)
5. x ^ -2c-2x+cx
x(x-2)+c(x-2)
(x+c)(x-2)
5. x^ -2c-2x+cx
x(x-2)+c(x-2)
(x+c)(x-2)
6.6p^+6-4p-9p
2(3-2p)-3p(3-2p)
(2-3p)(3-2p)
7.pa+qa-ra+rb-qb-pb
a(p+q-r)-b(p+q-r)
(a-b)(p+q-r)
參考: ME~~
2006-11-03 1:57 am
1.
st - 8s - 2t+16
=(st - 8s) - (2t-16)
=s(t-8)-2(t-8)
=(s-2)(t-8)
2.
4xy - 3y + 3z - 4xz
=y(4x-3)+z(4x-3)
=(y+z)(4x-3)
3.
xyp - xyq+3p-3q
=xy(p-q)+3(p-q)=(xy+3)(p-q)
4.
x 2次-x+3x-3
=x(x-1)+3(x-1)=(x+3)(x-1)
5.
x 2次 -2c-2x+cx
=x^2-2x-2c+cx
=x(x-2)+c(x-2)=(x+c)(x-2)
6.
6p2次+6-4p-9p
=6p2次-4p+6-9p
=2p(3p-2)-3(3p-2)
=(2p-3)(3p-2)
7.
pa+qa-ra+rb-qb-pb
=a(p+q-r)-b(p+q-r)
=(a-b)(p+q-r)
st - 8s - 2t+16
=(st - 8s) - (2t-16)
=s(t-8)-2(t-8)
=(s-2)(t-8)
2.
4xy - 3y + 3z - 4xz
=y(4x-3)+z(4x-3)
=(y+z)(4x-3)
3.
xyp - xyq+3p-3q
=xy(p-q)+3(p-q)=(xy+3)(p-q)
4.
x 2次-x+3x-3
=x(x-1)+3(x-1)=(x+3)(x-1)
5.
x 2次 -2c-2x+cx
=x^2-2x-2c+cx
=x(x-2)+c(x-2)=(x+c)(x-2)
6.
6p2次+6-4p-9p
=6p2次-4p+6-9p
=2p(3p-2)-3(3p-2)
=(2p-3)(3p-2)
7.
pa+qa-ra+rb-qb-pb
=a(p+q-r)-b(p+q-r)
=(a-b)(p+q-r)
參考: me
2006-11-03 1:55 am
1. st - 8s - 2t+16
=s(t-8)-2(t-8)
=(t-8)(s-2)
2.4xy - 3y + 3z - 4xz
=y(4x-3)-z(4x-3)
=(y-z)(4x-3)
3.xyp - xyq+3p-3q
=xy(p-q)+3(p-q)
=(xy+3)(p-q)
4.x^2-x+3x-3
=x^2+2x-3
=(x+3)(x-1)
5.x^2-2c-2x+cx
=x^2-2x+cx-2c
=x(x-2)+c(x-2)
=(x+c)(x-2)
6.(6p)^2+6-4p-9p
=36p^2-13p+6
=(9x-6)(4x-1)
7.pa+qa-ra+rb-qb-pb
=a(p+q-r)-b(p+q-r)
=(a-b)(p+q-r)
=s(t-8)-2(t-8)
=(t-8)(s-2)
2.4xy - 3y + 3z - 4xz
=y(4x-3)-z(4x-3)
=(y-z)(4x-3)
3.xyp - xyq+3p-3q
=xy(p-q)+3(p-q)
=(xy+3)(p-q)
4.x^2-x+3x-3
=x^2+2x-3
=(x+3)(x-1)
5.x^2-2c-2x+cx
=x^2-2x+cx-2c
=x(x-2)+c(x-2)
=(x+c)(x-2)
6.(6p)^2+6-4p-9p
=36p^2-13p+6
=(9x-6)(4x-1)
7.pa+qa-ra+rb-qb-pb
=a(p+q-r)-b(p+q-r)
=(a-b)(p+q-r)
2006-11-03 1:55 am
你想解開佢?
1. st-8s-2t+16
=(st-8s)-(2t-16)
=s(t-8)-2(t-8)
=(s-2)(t-8)
2. 4xy-3y+3z-4xz
=(4xy-3y)+(3z-4xz)
=y(4x-3)+z(3-4x) <-把他*-1 會得出 -z(-3+4x)
=(y-z)(4x-3)
3. xyp-xyq+3p-3q
=(xyp-xyq)+(3p-3q)
=xy(p-q)+3(p-q)
=(xy+3)(p-q)
4. x(square)-x+3x-3
=x(x-1)+3(x-1)
=(x+3)(x-1)
咁多既= =
5.x(square)-2c-2x+cx
=x(square)-2x-2c+cx
=x(x-2)-c(-2+x)
=x(x-2)-c(x-2)
=(x-c)(x-2)
6. 6p(square)+6-4p-9p
=6p2次-4p+6-9p
= 2p(3p-2)+3(2-3p) <-*-1
=(2p-3)(3p-2)
終於最後= =真係有d煩
pa+qa-ra+rb-qb-pb
pa-pb+qa-qb-ra+rb
p(a-b)+q(a-b)-r(a-b)
(p+q-r)(a-b)
做完 應該無錯= =我做左好耐
1. st-8s-2t+16
=(st-8s)-(2t-16)
=s(t-8)-2(t-8)
=(s-2)(t-8)
2. 4xy-3y+3z-4xz
=(4xy-3y)+(3z-4xz)
=y(4x-3)+z(3-4x) <-把他*-1 會得出 -z(-3+4x)
=(y-z)(4x-3)
3. xyp-xyq+3p-3q
=(xyp-xyq)+(3p-3q)
=xy(p-q)+3(p-q)
=(xy+3)(p-q)
4. x(square)-x+3x-3
=x(x-1)+3(x-1)
=(x+3)(x-1)
咁多既= =
5.x(square)-2c-2x+cx
=x(square)-2x-2c+cx
=x(x-2)-c(-2+x)
=x(x-2)-c(x-2)
=(x-c)(x-2)
6. 6p(square)+6-4p-9p
=6p2次-4p+6-9p
= 2p(3p-2)+3(2-3p) <-*-1
=(2p-3)(3p-2)
終於最後= =真係有d煩
pa+qa-ra+rb-qb-pb
pa-pb+qa-qb-ra+rb
p(a-b)+q(a-b)-r(a-b)
(p+q-r)(a-b)
做完 應該無錯= =我做左好耐
收錄日期: 2021-04-13 13:49:55
原文連結 [永久失效]:
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