inequalities

(2x+1)^2 ≥ (3x - 4)^2
4x^2 + 4x + 1 ≥ 9x^2 - 24x +16
0 ≥ 5x^2 - 28x +15

0 ≥ (5x-3)(x-5)
Therefore,
Case 1:
(5x-3)≤0 and (x-5)≥0
x≤3/5 and x≥5 (Impossible)
Case 2:
(5x-3)≥0 and (x-5)≤0
x≥3/5 and x≤5

(2x + 1) ^ 2 } (3x - 4) ^2


2x + 1 } 3x - 4 & 2x + 1 } -(3x - 4)

1 + 4 } 3x - 2x & 2x + 3x } 4 - 1

x { 5 & 5x } 3

3/5 { x { 5

2006-11-02 09:50:14 補充：
} greater than or equal{ smaller than or equal

(2x+1)^2 is greater than or equal to (3x - 4)^2

4x^2+4x+1 is greater than or equal to 9x^2-24x+16

5x^2-28x+15 is smaller than or equal to 0

(x-5)(5x-3) is smaller than or equal to 0

3/5 is smaller than or equal to x is smaller than or equal to 5

Hopes can help u