1. (u^8v^9)/(u^7v^2)X (uv^7)
2. (-7a^3b^2)X(-8b^4c^5)/(-14a^2bc^4)
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想問2條f.1 數學題 急..............
2006-11-02 5:20 am
回答 (4)
2006-11-02 5:44 am
✔ 最佳答案
1. (u^8v^9)/(u^7v^2)X (uv^7)(u^8 v^9)/(u^7 v^2)X (u v^7)
=u^(8-7+1) v^(9-2+7)
=u^2 v^14
2. (-7a^3b^2)X(-8b^4c^5)/(-14a^2bc^4)
(-7a^3 b^2)X(-8b^4 c^5)/(-14a^2 b c^4)
=-(7x8 / 14) a^(3-2) b^(2+4-1) c^(5-4)
=-4a b^5 c
2006-11-02 6:21 am
1. (u^8v^9)/(u^7v^2)X (uv^7)
=u^(8-7+1) v^(9-2+7)
=u^2 v^14
2. (-7a^3b^2)X(-8b^4c^5)/(-14a^2bc^4)
=-(7x8 / 14) a^(3-2) b^(2+4-1) c^(5-4)
=-4a b^5 c
must correct~
=u^(8-7+1) v^(9-2+7)
=u^2 v^14
2. (-7a^3b^2)X(-8b^4c^5)/(-14a^2bc^4)
=-(7x8 / 14) a^(3-2) b^(2+4-1) c^(5-4)
=-4a b^5 c
must correct~
參考: Teacher
2006-11-02 5:46 am
1.
(u^8v^9)/(u^7v^2)X (uv^7)
= u^(8-7+1) v^(9-2+7)
= u^2 v^14
2. (-7a^3b^2)X(-8b^4c^5)/(-14a^2bc^4)
= [(-7)(-8)/(-14)][a^(3-2)b^(2+4-1)c^(5-4)]
= -4ab^5c
(u^8v^9)/(u^7v^2)X (uv^7)
= u^(8-7+1) v^(9-2+7)
= u^2 v^14
2. (-7a^3b^2)X(-8b^4c^5)/(-14a^2bc^4)
= [(-7)(-8)/(-14)][a^(3-2)b^(2+4-1)c^(5-4)]
= -4ab^5c
參考: me
收錄日期: 2021-04-12 23:00:42
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061101000051KK04247