How much work must you do to push a 10kg block of steel across a steel table at a steady speed of 1.0m/s for 3.0s?What is your power output while doing so?
Answer:176.4J/58.8J
Steps?
Power
2006-11-01 10:38 pm
回答 (1)
2006-11-02 1:44 am
✔ 最佳答案
Assume coefficient of friction for steel on steel is 0.588Force acting on the block = 0.588 x 10kg x 10m/s^2 = 58.8N
Distance travelled in 3s = 1m/s x 3s = 3m
Therefore, work done on the block = 58.5N x 3m = 176.4J
Power output = work done/second = 176.4J/3s = 58.8W
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