✔ 最佳答案
Let P(n)be the proposition,
1/1.2.3+1/2.3.4+....+1/n(n+1)(n+2)=n(n+3)/4(n+1)(n+2)
when n=1,
L.H.S=1/(1.2.3)=1/6
R.H.S=1(1+3)/4(2)(3)=4/24=1/6
L.H.S=R.H.S
So,P(1)is true.
Assume that P(k)is true,
i.e. 1/1.2.3+1/2.3.4+....+1/k(k+1)(k+2)=k(k+3)/4(k+1)(k+2)
when n=k+1,
L.H.S=1/1.2.3+1/2.3.4+....+1/k(k+1)(k+2)+1/(k+1)(k+2)(k+3)
=k(k+3)/4(k+1)(k+2)+1/(k+1)(k+2)(k+3)
=[k(k+3)^2+4]/4(k+1)(k+2)(k+3)
=(k+1)(k+1)(k+4)/4(k+1)(k+2)(k+3)
=(k+1)(k+4)/4(k+2)(k+3)
R.H.S=(k+1)(k+3+1)/4(k+1+1)(k+2+1)
=(k+1)(k+4)/4(k+2)(k+3)
L.H.S=R.H.S
So, P(k+1)is true.
By the principle of M.I.,P(n) is true for all integers n.