有一題數學唔識做，請幫忙？

2x^2 -7x +3 =0
(2x-1) (x -3) =0
x=1/2 or x=3
if y is the reciprocal (倒數)of x
y= 2 or y= 1/3
y-2=0 or y- 1/3=0
(y-2)(y-1/3)=0
y^2-2 1/3y+2/3=0
3y^2-7y+2=0

so the equation should be 3x^2+7x+2=0

2x^2 -7x +3 =0
(2x-1)(x-3)=0
x=1/2 or x =3
根的倒數:
x=2 or x=1/3, i.e. 3x=1

so the required equation is:
(x-2)(3x-1)=0
3x^2-7x+2=0

2006-11-03 13:16:49 補充：
樓下steps o岩, 答案大意寫錯左