方程algebra
數學中一方程2
1:x-6=x-3/4 x=?
2:2y+1/5=3-y y=?
3:8x+ 3x-7/2《二份之三X減七》=6
4:b/3《三份之b》-(5-b)=3
5:x/3-x/2=1
6:3/4y《四份之三y》=1-1/2y《二份之一y》
回答 (3)
✔ 最佳答案
1.
x-6 = x-3/4
4x-24=x-3
3x=21
x=7
2.
2y+1/5 = 3-y...(全部乘5)
10y+1=15-5y
15y=14
y=15/14
3. 8x+ 3x-7/2=6...(全部乘2)
16x+3x-7=12
19x=19
x=1
4.
b/3-(5-b) = 3...(全部乘3)
b-15+3b=9
4b=24
b = 6
5.
x/3-x/2 = 1...(全部乘6)
2x-3x=6
-x=6
x = -6
6.
3/4y = 1-1/2y
3/4y+1/2y=1
5/4y=1
5=4y
y=5/4
[1]
x-6=x-3/4
x=3/4-6
x=-5+1/4
[2]
2y+1/5=3-y
3y=3-1/5
y=14/5/3
y=14/15
[3]
8x+ 3x-7/2《二份之三X減七》=6
11x=19/2
x=19/22
[4]
b/3《三份之b》-(5-b)=3
b/3-5+b=3
b+b/3=8
2b=24
b=12
[5]
x/3-x/2=1
2x/6-3x/6=1
-1x=6
x=-6
[6]
3/4y《四份之三y》=1-1/2y《二份之一y》
3/4y+2/4y=1
5/4y=1
5y=4
y=4/5
2006-10-30 21:34:38 補充:
第一題是(-5+1/4)
參考: me
1.
x-6 = x-3/4
x-x = -3/4-6
so no solution
2.
2y+1/5 = 3-y
2y+y = 3-1/5
3y = 14/5
y = 14/15
3.
is it 8x+(3/2)x-7 = 6??
(8+3/2)x = 6+7
(19/2)x = 13
x = 26/19
or
8x+3x-7/2 = 6??
(8+3)x = 6+7/2
11x = 19/2
x = 22/19
4.
b/3-(5-b) = 3
b/3-5+b = 3
(4/3)b = 3+5
(4/3)b = 8
b = 6
5.
x/3-x/2 = 1
(1/3-1/2)x = 1
-1/6x = 1
x = -6
6.
3/4y = 1-1/2y
(3/4+1/2)y = 1
5/4y = 1
y = 4/5
收錄日期: 2021-04-13 13:25:48
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