C+C+C-D-D=12
D+D+D-C-C=2
C=?;D=?
C=?;D=?
2006-10-31 1:39 am
回答 (5)
2006-10-31 1:49 am
C+C+C-D-D=12 ---- 1
D+D+D-C-C=2 ------ 2
By 1:
C+C+C-D-D=12
3C-2D=12
C=(12+2D)/3-------------3
By 2:
D+D+D-C-C=2
3D-2C=2----------------4
Sub 3 into 4:
3D-2[(12+2D)/3]=2
9D-24-4D=6
5D-24=6
5D=30
D=6 -----------------------5
Sub 5 into 1:
3C-2(6)=12
3C=12+12
C=24/3
C=8
So C=8, D=6
D+D+D-C-C=2 ------ 2
By 1:
C+C+C-D-D=12
3C-2D=12
C=(12+2D)/3-------------3
By 2:
D+D+D-C-C=2
3D-2C=2----------------4
Sub 3 into 4:
3D-2[(12+2D)/3]=2
9D-24-4D=6
5D-24=6
5D=30
D=6 -----------------------5
Sub 5 into 1:
3C-2(6)=12
3C=12+12
C=24/3
C=8
So C=8, D=6
參考: me
2006-10-31 1:43 am
c=6
d=3
d=3
收錄日期: 2021-04-12 19:05:20
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061030000051KK04112