help me~f.4 a math

given that the quadratic equation x^2 - 2(3m+1)x + 7(2m+3)=0

has two equal roots.find the value of m.hence,solve the

equation for each value of m
discriminant=0
4[3m+1]^2-28(2m+3)=0
4(9m^2+6m+1)-56m-84=0
36m^2+24m+4-56m-84=0
36m^2-32m-80=0
m=2 or m=-10/9
for m=2
x^2 - 2(3m+1)x + 7(2m+3)=0
x^2 - 14x + 49=0
(x-7)^2=0
x=7
for m=-10/9
x^2 - 2(3m+1)x + 7(2m+3)=0
x^2 +(14/3)x + 49/9=0
3x^2 +42x + 49=0
(3x+7)^2=0
x=-7/3