c programme功課.......急

💻 軟件台程式編寫及設計

[匿名]

2006-10-30 9:10 am

如果我想計 x = (10x+2)^(1/3) 於c中可以點樣計?
因為我寫 x=pow(10x+2,(float)1/3)
計得唔o岩ge佢
出哩ge ans係:26815615873518931787257526688330301811796810000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000.000000????
點解ge?
麻煩幫幫忙.....功課......急
唔該晒

更新1:

我用o左你ge 建議=~="都係error........

更新2:

#include #include main() { float x,y,i,a,b,r; i=0; printf("Find the root of the following equation: x^3-10x-2=0 \n"); printf("Please Enter a number x between 0 to 10: ");

更新3:

scanf("%f",&x); printf("Please Enter the Relative Error of x:"); scanf("%f",&y); a=pow(10*2+2,double(1.f/3.f)); b=fabs(a-x)/x;

更新4:

while (b y) { i=i+1; x=a; a=pow(10*x+2,(float) 1/3); b=fabs(a-x)/x;} r=a; printf("The Root of the eqaution is:"); printf("%f",&r); }

回答 (2)

auyeung_ks

2006-10-31 6:16 am

✔ 最佳答案

double x = pow ((double)(10*2 + 2) , (double)(1.0f / 3.0f));

剛剛試左, work先卑你

問題係：
pow() does not have an overloaded function for (int and double) as parameters. You must explicitly cast both parameters to double. You did it for the second parameter, double(1.0f/3.0f) but the first one remained to be an int.

explaination:
pow(int a, double b) Wrong
pow(double a, double b) YES

As to why you got a garbage answer to be the first place I cannot explain. The compiler should had caught the function overloaded error.

👍 0 👎 0

Terence CHAN

2006-10-30 10:27 am

x=pow(10x+2,(float)1/3)
改做:
x = pow( ( 10 * 2) + 2 ), double(1.f/3.f))

參考: my programming knowledge

👍 0 👎 0

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