F4.certificate Maths功課...幫手!!!MC Question~~~

2006-10-30 4:13 am
1. The following is two graphs of the same shap. If graph(I) is y=f(x),then which of the followings can be the graph(II)?

A. y=f(x+4)+3

B. y=f(x+2)+7

C.y=f(x+2)+4

D.y=f(x-2)+7

2. Reflect the graph y =(x-h)^2+k about the x-axis,and then move to the right h unit.
Then what is the equation of the new graph?

A.y=x^2+k

B.y=(x-2h)^2+k

C.y= -X^2-k

D.y= -(x-2h)^2-k

回答 (1)

2006-10-31 6:15 am
✔ 最佳答案
好簡單咁答妳一d好 general ge 解決方法
#1
妳可以咁諗
y=f(x)係一條U-shape線
題目而家問妳ABCD邊條線係同y=f(x)係同一個樣
所以, 妳可以assume y = f(x) = x^2
由於妳可以從4個ans睇到, 佢地只係y=f(x)個圖平移之後ge樣
[因為y=f(x)→y=f(x-h)+k 就係y=f(x)個圖shift h units to the right and k units upward]
所以4個ans都會出同一個樣ge曲線, ie 4個ans都岩
Therefore, 題目出錯

#2
題目要將個圖向x反轉, 再向右移h units
如果比我做, 我會先做平移,再做reflect
方法係點呢?
因為如果做完reflect先做shifting,圖就係向右移
但係我而家做左shifting先, 所以一開始係向→左移← h units
而向左移h units,個formula就會變成 y = x^2 +k
[因為如果向右移, 就會y=f(x)→y=f(x-h)
如果向左移, 就會→y=f(x+h)
而家佢條題目係y=(x-h)^2 + k 就會變成y=(x-h+h)^2 + k ie y = x^2 +k]
好啦,跟住做reflect
由數據上面咁做ge話呢, 如果條curve reflected by x-axis
就會 y=f(x)→ -y=f(x) → y= - f(x)
咁樣, y=x^2 +k就會變成 y= -x^2 - k
so, ans is C

如果妳要睇詳盡解釋,就下面↓(雖然唔知妳會唔會明)
由於而家條curve(y=x^2+k) ge lowest point係(0,k)
ie.條curve係u shape at h units above the origin
如果將佢reflected by x-axis
即係將佢成條curve反落去x-axis下面
咁就會變成 n shape at h units below the origin
寫番做equation ge 話就會變成y= -x^2-k
ie ans C
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