Please do one Maths
2006-10-30 2:33 am
The difference of two numbers is 8, and their sum is 88. Find the value of the larger number.
回答 (7)
2006-10-30 2:42 am
✔ 最佳答案
Let x be the larger number. Then the smaller number is x - 8The sum is 88. Therefore
x + (x - 8) = 88
2x - 8 = 88
2x = 96
x = 48
The larger number is 48.
2006-10-29 18:43:36 補充：
There is no need to solve the problem using simultaneous equations as we aim at finding the larger number ONLY.
2006-10-30 5:10 am
Let the larger number be x.
x+x-8=88
2x=96
x=48
So the larger number is 48.
x+x-8=88
2x=96
x=48
So the larger number is 48.
參考: my brain
2006-10-30 3:59 am
一條和差問題。
公式:
1.大數=(和+差)/2
2.小數=(和-差)/2
根據公式1,大數是:
(88+8)/2
=96/2
=48
公式:
1.大數=(和+差)/2
2.小數=(和-差)/2
根據公式1,大數是:
(88+8)/2
=96/2
=48
2006-10-30 2:48 am
Let the larger number be a, the smaller number be b.
∵The difference of two numbers is 8.
a-b=8
∴ b=a-8
∵Their sum is 88.
a+b=88
a+(a-8)=88
2a-8=88
2a=96
a=48
∴The larger number is 48
∵The difference of two numbers is 8.
a-b=8
∴ b=a-8
∵Their sum is 88.
a+b=88
a+(a-8)=88
2a-8=88
2a=96
a=48
∴The larger number is 48
2006-10-30 2:44 am
Let y be the larger number, that is the smaller number is (y -8)
y + (y - 8) = 88
2y - 8 = 88
2y = 96
y = 48
Hence, the value of the larger number is 48.
y + (y - 8) = 88
2y - 8 = 88
2y = 96
y = 48
Hence, the value of the larger number is 48.
2006-10-30 2:42 am
一個係 40...一個係48
x + y = 88.....(1)
x - y =8...(2)
form (2)
x - y =8
x = 8+y..... (3)
put (3) into (1)
x + y = 88
8+y+y =88
8+2y = 88
y =40
sub y =40 in (2)
x -40 =8
x=48
x + y = 88.....(1)
x - y =8...(2)
form (2)
x - y =8
x = 8+y..... (3)
put (3) into (1)
x + y = 88
8+y+y =88
8+2y = 88
y =40
sub y =40 in (2)
x -40 =8
x=48
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