1+2+3+.......9999
回答 (18)
✔ 最佳答案
49995000
2006-10-29 19:04:13 補充:
怎麼會想問這種問題呢?我算了許久答案不知有錯嗎?
1+2+3+...+9999
=(1+9999)x9999/2
=10000x9999/2
=99990000/2
=49995000
參考: 自己
1+2+3+.......9999=49995000
參考: me
(1+n)n/2
=(1 + 9999)9999/2
= 49995000
(1+9999)*9999/2
=10000*9999/2
=5000*9999
=49995000
參考: me
there is a equation for this
n x (n+1)/2
9999 x (10000)/2
= 49995000
(1+9999)x9999÷2=49995000
參考: my own knowledge
9999/2 再X(1+9999)=49995000
(1+9999)x9999
----------------------
2
=49995000
參考: me
(1+9999)9999/2
=49995000
參考: 自己
收錄日期: 2021-04-12 22:40:32
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