超級容易的數學題

👨🏻‍🏫 學術台數學

2006-10-29 5:17 am

1234567890+987654321*582-987456=?

回答 (9)

2006-10-29 5:43 am

✔ 最佳答案

用「先乘除，後加減」的原則去計這條數學題。
答案是 57604839525。

👍 0 👎 0

2006-10-29 6:32 am

1234567890+987654321*582-987456
=1234567890+(987654000+321)*582-(987654-198)*1000/1000
=1234567890+(987654000+321)*582-(987654000-198*1000)/1000
=1234567890+(987654000*582)+(321*582)-(987654000/1000)+(198)
=1234567890+(987654000*582/1000)+186822+198
=1234567890+187020+574814628000
=576049382900

👍 0 👎 0

2006-10-29 6:27 am

576048395256

參考: ｍｅ

👍 0 👎 0

2006-10-29 5:41 am

1234567890+987654321*582-987456=576048395256

參考: 計數機.....

👍 0 👎 0

2006-10-29 5:33 am

1234567890+987654321*582-987456=576048953

👍 0 👎 0

2006-10-29 5:25 am

等於５.760483953

👍 0 👎 0

HN

2006-10-29 5:25 am

要先乘除後加減,所以
1234567890+987654321*582-987456
=576048395256

參考: 自己

👍 0 👎 0

2006-10-29 5:21 am

1234567890+987654321*582-987456=?
=1923332339346

參考: me

👍 0 👎 0

2006-10-29 5:21 am

1234567890+987654321*582-987456=576048395256

👍 0 👎 0

收錄日期: 2021-04-12 22:34:34
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061028000051KK04873

檢視 Wayback Machine 備份