solving quadratic equations

2006-10-29 12:01 am
1) 4x^2+4x+1
2) 4x^2-44x+121
3) (3x+2)(3x+1)=20
4) (x+2)(3x-2)=(x+6)(2X+1)
5) (x-3)^2=(1-4x)^2

3-5有兩個答案..thx

回答 (2)

2006-10-29 12:15 am
✔ 最佳答案
(1)
4x^2+4x+1=0
(2x+1)^2=0
2x+1=0
x=-1/2

(2)
4x^2-44x+121=0
(2x-11)^2=0
2x-11=0
x=11/2

(3)
(3x+2)(3x+1)=20
9x^2+9x+2=20
9x^2+9x-18=0
9(x^2+x-2)=0
x^2+x-2=0
(x-1)(x+2)=0
x=1 or x=-2

(4)
(x+2)(3x-2)=(x+6)(2x+1)
3x^2+4x-4=2x^2+13x+6
x^2-9x-10=0
(x+1)(x-10)=0
x=-1 or x=10

(5)
(x-3)^2=(1-4x)^2
x^2-6x+9=16x^2-8x+1
15x^2-2x-8=0
(3x+2)(5x-4)=0
x=-2/3 or 4/5
2006-10-29 12:28 am
1. 4x^2+4x+1= (2x+1)(2x+1)
x=-1/2
2. 4x^2-44x+121= (2x+11)(2x+11)
x=-11/2
3. (3x+2)(3x+1)=20
9x^2+3x+6x+2=20
9x^2+9x+2=20
9x^2+9x-18=0
(9x+18)(x-1)=0
x=-2 or 1
4. (x+2)(3x-2)=(x+6)(2x+1)
3x^2-2x+6x-4=2x^2+x+12x+6
x^2+4x-4=13x+6
x^2-9x-10=0
(x-10)(x+1)=0
x=10 or -1
5. (x-3)^2=(1-4x)^2
x^2-6x+9=16x^2+8x+1
0=15x^2+14x-8
0= (3x+4)(5x-2)
x=-4/3 or 2/5


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