✔ 最佳答案
Let x be the price and q be the quantity purched in 300
X . Q = 300 --------- (1)
(X - 0.3) (Q + 20) = 308----------(2)
(2) ====> XQ - 0.3Q + 20X - 6 = 308 --------- (3)
Put (1) into (3) ====> 300 - 0.3Q + 20 X-6 = 308
Q = (20X - 14) / 0.3-------- (4)
Put (4) into (1)
(X) (20X - 14) / 0.3 = 300
20X^2 -14X = 90
20X^2 - 14 X -90=0
10X^2 - 7X - 45 = 0
(2x – 5)(5x + 18) = 0
X = 2.5 or – 3.6 (rejected)
the reduced price is x – 0.3 = 2.2
2006-10-28 11:38:33 補充:
the last steps should be 10X^2 - 7X - 45 = 0 (2x – 5)(5x + 9) = 0 X = 2.5 or – 1.8 (rejected) the reduced price is x – 0.3 = 2.2