5(w/3 -4)-[(3-w)/6)]=41/2
w=?
請列明步驟~thx！
f.1 maths , plz help!! ((fast......))
2006-10-28 4:40 am
回答 (6)
2006-10-28 4:45 am
✔ 最佳答案
5(w/3 -4)-[(3-w)/6)]=41/2(5w/3w-4w)-3/6-w/6)=20.5
5w-(-1w)-0.5-w/6=20.5
6w-w=20.5+0.5
5w=21
w=4.2
我都唔知啱唔啱...
2006-10-27 20:49:55 補充：
整番靚D先................5(w/3 -4)-[(3-w)/6)]=41/2[5w/3w+(-4w)]-[3/6+(-w/6)]=20.5................5w-(-1w)-0.5-w/6=20.5....................................6w-w=20.5+0.5...................................5w=21.....................................w=4.2
參考: 自己
2006-10-28 4:55 am
5(w/3 -4)-[(3-w)/6)]=41/2
(5w/3 -20)-(3/6 -w/6)=20.5
(5w/3 + w/6)-20.5=20.5
10w/6+ w/6=41
11w/6=41
w=246/11
(5w/3 -20)-(3/6 -w/6)=20.5
(5w/3 + w/6)-20.5=20.5
10w/6+ w/6=41
11w/6=41
w=246/11
2006-10-28 4:52 am
5(w/3 -4)-[(3-w)/6)]=4 1/2
5w/3 - 4 - (3-w)/6 = 4.5
5w/3 - (3-w)/6 = 8.5
10w-(3-w)=51
10w-3+w=51
11w=54
w=54/11
5w/3 - 4 - (3-w)/6 = 4.5
5w/3 - (3-w)/6 = 8.5
10w-(3-w)=51
10w-3+w=51
11w=54
w=54/11
2006-10-28 4:49 am
5(w/3 -4)-[(3-w)/6)]=41/2
5w/3-20-[(3-w)/6)]=41/2
6*(5w/3-20-[(3-w)/6)])=(41/2)*6
10w-120-3+w=123
11w=120+123+3
11w=246
w=246/11
5w/3-20-[(3-w)/6)]=41/2
6*(5w/3-20-[(3-w)/6)])=(41/2)*6
10w-120-3+w=123
11w=120+123+3
11w=246
w=246/11
2006-10-28 4:47 am
5(w/3 -4)-[(3-w)/6)]=41/2
(5w/3w-4w)-3/6-w/6)=20.5
5w-(-1w)-0.5-w/6=20.5
6w-w=20.5+0.5
5w=21
w=4.2
(5w/3w-4w)-3/6-w/6)=20.5
5w-(-1w)-0.5-w/6=20.5
6w-w=20.5+0.5
5w=21
w=4.2
收錄日期: 2021-04-12 23:43:29
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061027000051KK03710