1.(3^-1-3)/6^-2
我係測驗做錯左呢一題,有冇人可以help me?
有關零指數既負指數既問題
2006-10-28 3:44 am
回答 (3)
2006-10-28 4:36 am
(3^-1-3)/6^-2
= 1/3*27/1/36
= 36/81
= 1/3*27/1/36
= 36/81
2006-10-28 3:47 am
(3^-1-3)/6^-2
= [(1/3) -3]/ (1/36)
= (-11/3)x36
= -96
2006-10-27 19:53:39 補充：
更正更正(3^-1-3)/6^-2= [(1/3) -3]/ (1/36)= (-8/3)x36= -96
= [(1/3) -3]/ (1/36)
= (-11/3)x36
= -96
2006-10-27 19:53:39 補充：
更正更正(3^-1-3)/6^-2= [(1/3) -3]/ (1/36)= (-8/3)x36= -96
收錄日期: 2021-04-12 22:58:24
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061027000051KK03350