let f(x)=x^99+k
when f(x) is divided by x+1,the remainder is 1.find the value of k
已搵到k係2,下一條
hence, find the remainder when9^99 is devided by10
點做呀?可唔可以詳細d講解
form4數學
2006-10-27 5:08 am
回答 (1)
2006-10-27 5:15 am
✔ 最佳答案
f(x)=x^99+2=(x+1)q(x)+1當x=9,
9^99+2=10．N+1 (N是整數)
9^99=10N-1
9^99=10(N-1)+(10-1)
9^99=10(N-1)+9
所以9^99除10後餘數是9
ok^^?
參考: 自己
收錄日期: 2021-04-12 23:22:49
原文連結 [永久失效]:
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