help me! form1數學

2006-10-27 4:23 am
三個連續數之和減去其最小數的4倍之結果為1。求該三個數。
(要過程)

回答 (5)

2006-10-27 4:34 am
✔ 最佳答案
設最小數為Q。

[Q+(Q+1)+(Q+2)]-4Q=1
Q+Q+1+(Q+2)-4Q=1
Q+Q+1+Q+2-4Q=1
3Q+1+2-4Q=1
3Q-4Q=1-1-2
-1Q=-2
-Q=-2
Q=2

-Q=-2
點解變左
Q=2
因為負負得正
參考: 自己
2006-10-29 12:46 am
let xbe the smallest number

(x+x+1+x+2)-4x=1

3x+3-4x=1

x=2

the three are 2,3and4



Prove :

2+3+4-=9
2*4=-8
9-8=1

2006-10-28 16:47:30 補充:
2*4=-8not -8,is 8
2006-10-27 4:31 am
設三個數中, 最小的為x
(x + x+1 + x+2)-4x = 1
(3x+3)-4x = 1
3-x = 1
3-x+x-1 = 1+x-1--------(兩邊加入 x-1)
3-1 = x
x = 2

該三個連續數為 2,3,4
2006-10-27 4:28 am
Let X be the smallest number
X+X+1+X+2-4X=1x
x=2

2,3,4
參考: me
2006-10-27 4:27 am
let x be the smallest number
the three numbers are x,(x+1), and (x+2)
x+(x+1)+(x+2)-4x=1
3x+3-4x=1
-x=-2
x=2

so the smallest number is 2
the three numbers are 2, 3 and 4


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