✔ 最佳答案
1.Let the two roots of 8x^2-ax+9=0 be h,k
set h=2k
sum of root:h+k=a/8
product of root:hk=9/8
3k=a/8
2k^2=9/8
a=18
8x^2-18x+9=0
x=3/2 or 3/4
2.Let the two roots of kx^2+4x+k^2-21=0 be a, b
product of root:ab=4=k^2-21/k
k=7 or -3
3(a).Let the roots of x^2+a(3a-5)x=2(x+4a) be h, k
k=-h
sum of root:h+(-h)=0=-a(3a-5)
a=5/3
3(b).a=0?
then x^2+(0)(3(0)-5)x=2(x+4(0))
x^2-2x=0
x=2 or 0
4.a, b are the root of x^2-5x+k=0...(1)
1/2a+1, 1/2b+1 are the root of 35x^2+nx+1=0...(2)
From (1),
sum of root:a+b=5
product of root:ab=k
From (2),
sum of root: (1/2a+1)+(1/2b+1)=-n/35...(3)
product of root: (1/2a+1)(1/2b+1)=1/35...(4)
From (3),
(a+b)/2+2=-n/35
5/2+2=-n/35
n=-157.5
From (4),
(1/2a+1)(1/2b+1)=1/35
ab/2+(a+b)/2+1=1/35
ab/2+(5)/2+1=1/35
ab=k=-243/35
5.Let the root of x^2+px+q=0 be a, b
a-b=2
sum of root: a+b=-p
product of root: ab=q
(a+b)^2-4ab=(a-b)^2
p^2-4q=4
p^2=4+4q
6.let the two root of ax^2+bx+c=0 be h, k
h^2+k^2=4
sum of root: h+k=-b/a
product of root: hk=c/a
(h+k)^2-2hk=h^2+k^2=4
(-b/a)^2-2(c/a)=4
b^2-2ac=4a^2
b^2=2ac+4a^2
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