Factorize the following expressions
1.2(x-y)(2次方)+8(x-y)+8
2.x(2次)-4y(2次)-3x-6y
Maths (f.2)
2006-10-26 3:28 am
回答 (3)
2006-10-26 3:41 am
✔ 最佳答案
1.2(x-y)²+8(x-y)+8=2[(x-y)+2]²
=2(x-y+2)²
2.x²-4y²-3x-6y
=(x+2y)(x-2y)-3(x+2y)
=(x+2y)[(x-2y)-3]
=(x-2y-3)(x+2y)
2006-10-26 3:42 am
1.2(x-y)(2次方)+8(x-y)+8
=2(x(2次方)-y(2次方))+8x-8y+8
=2x(2次方)-y(2次方)+8x-8y+8
=10x(2次方)-9y(2次方)+8
2.x(2次)-4y(2次)-3x-6y
=2x-8y-3x-6y
=-x-14y
=2(x(2次方)-y(2次方))+8x-8y+8
=2x(2次方)-y(2次方)+8x-8y+8
=10x(2次方)-9y(2次方)+8
2.x(2次)-4y(2次)-3x-6y
=2x-8y-3x-6y
=-x-14y
2006-10-26 3:31 am
1.
2(x - y) ^ 2 + 8(x - y ) + 8
= 2 [(x - y)^ 2 + 4(x - y) + 4]
= 2 [(x - y) - 2]^2
= 2(x - y - 2)^2
2.
x^ 2 - 4y^ 2 - 3x - 6y
= ( x + 2y)(x - 2y) - 3( x - 2y)
= (x - 2y)(x + 2y - 3)
2(x - y) ^ 2 + 8(x - y ) + 8
= 2 [(x - y)^ 2 + 4(x - y) + 4]
= 2 [(x - y) - 2]^2
= 2(x - y - 2)^2
2.
x^ 2 - 4y^ 2 - 3x - 6y
= ( x + 2y)(x - 2y) - 3( x - 2y)
= (x - 2y)(x + 2y - 3)
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