✔ 最佳答案
I don't really understand exactly what u want to ask so i give u some idea about these graphes
s-t is the graph of displacement vs time
v-t is the graph of velocity vs time
a-t is the graph of acceleration vs time
displacement, velocity and acceleration is a vector =>has a direction =>can be negative value
**remember they are different from distance, speed for displacement and velocity
If u do calculus u will know that the gradient(dy/dx or rate of change) of velocity is the function of acceleration
and intergral(anti-differentiation, area under the curve) the function of acceleration is the velocity
below will also show u the relationship with displacement:
d(displacement)/dx = velocity
d(velocity)/dx = acceleration
∫acceleration dx = velocity
∫velocity dx = displacement
so when u doing the s-t, v-t, & a-t graph,
if the question given the s-t graph then just find the gradient of each point then u will get v-t graph and so on to get the a-t graph
if the question given the a-t graph then just find the area under the curve will give u the v-t and so on to get the s-t graph